document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739>Question 739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a hard time trying to determine the slope intercept form of an equation of a line that passes through the points (6, -2) and has a y - intercept of -2. can you please explaine steps-by-steps </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #251 by </B><A HREF=/tutors/aboutme.mpl?userid=raisetoana><B>raisetoana(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=raisetoana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the slope intercept form of the equation of a line, use the following formula:\r<BR>\n" );
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document.write( "y - y1 = m(x - x1)   where (x1,y1) is the given point and m is the slope\r<BR>\n" );
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document.write( "In order to use this equation, we will need to find the slope of the line since you need the slope and a point to find the equation of a line.\r<BR>\n" );
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document.write( "slope = m = rise/run<BR>\n" );
document.write( "      = (y2-y1)/(x2-x1)   (x1,y1) = (6,-2)  (x2,y2) = y intercept = (0,-2)<BR>\n" );
document.write( "      = ((-2)-(-2))/((0)-(6))<BR>\n" );
document.write( "      = 0<BR>\n" );
document.write( "plug in the known values:<BR>\n" );
document.write( "y - (-2) = (0)(x - 6 )<BR>\n" );
document.write( "y + 2    = 0<BR>\n" );
document.write( "       y = -2\r<BR>\n" );
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document.write( "This is your equation. </SPAN>\n" );
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