document.write( "Question 351127: A line goes through the point (4,-3) and has a slope of -3/2. Graph this line. \n" ); document.write( "
Algebra.Com's Answer #250962 by nerdybill(7384)\"\" \"About 
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A line goes through the point (4,-3) and has a slope of -3/2. Graph this line.
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\n" ); document.write( "The equation can be found by plugging the given info into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - (-3) = (-3/2)(x - 4)
\n" ); document.write( "y + 3 = (-3/2)x + 6
\n" ); document.write( "y = (-3/2)x + 3
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"1.5+x+%2B+1+y+=+3\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-1.5%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 3/1.5 = 2.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 3/1 = 3.
  • Slope is -1.5/1 = -1.5.
  • Equation in slope-intercept form: y=-1.5*x+3.
\"graph%28+500%2C+500%2C+2-8%2C+2%2B8%2C+3-8%2C+3%2B8%2C+-1.5%2Ax%2B3+%29+\"\n" ); document.write( "
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