document.write( "Question 351102: A tourist bus travels 120 kilometers to its destination. The average speed returning is twice the average speed going and the time for a round trip is 5 hours. What is the average speed of the bus in going to its destination? Thank you so much. \n" ); document.write( "

Algebra.Com's Answer #250954 by ewatrrr(24785) $\"\"$ $\"About$

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Hi,
\n" ); document.write( "*Note: distance to and from the same. D = r*t
\n" ); document.write( "Let r be the speed and t the time it takes to travel to its destination
\n" ); document.write( "Return speed is then 2*r and the time left for that trip is (5hr-t)
\n" ); document.write( ".
\n" ); document.write( "Question states:
\n" ); document.write( "going to destination
\n" ); document.write( "r*t = 120km
\n" ); document.write( "r = 120km/t
\n" ); document.write( ".
\n" ); document.write( "returning from destination (substitute and solve for t
\n" ); document.write( " $\"%28240%2Ft%29%285-t%29=+120\"$
\n" ); document.write( ".
\n" ); document.write( "simplify and solve:
\n" ); document.write( "240(5hr-t) = 120t
\n" ); document.write( "1200hr - 240t = 120t
\n" ); document.write( "1200hr = 360t
\n" ); document.write( "3 1/3 hr = t
\n" ); document.write( ".
\n" ); document.write( "Finding rate going to destination
\n" ); document.write( "r*(10hr/3)= 120mi
\n" ); document.write( "r = 36 mi/hr \n" ); document.write( "

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