document.write( "Question 39666: I can not figure out for the life of me how to do this. I have tried so many times, please, HELP.\r
\n" ); document.write( "\n" ); document.write( "Solve:
\n" ); document.write( "3log(5x)+4log(2x)=3
\n" ); document.write( "log(125x^3)+log(16x^4)=3\r
\n" ); document.write( "\n" ); document.write( "Have I done it right so far? For some reason it seems wrong.Please help me!!
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Algebra.Com's Answer #25094 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You are correct as far as you have gone.
\n" ); document.write( "\"log%28125x%5E3%29%2Blog%2816x%5E4%29+=+3\" Now apply the \"product rule\" for logarthms:\"log%28M%29%2Blog%28N%29+=+logMN\"
\n" ); document.write( "\"log%28%28125x%5E3%29%2816x%5E4%29%29+=+3\" Simplify.
\n" ); document.write( "\"log%282000x%5E7%29+=+3\" Convert to exponential form.
\n" ); document.write( "\"10%5E3+=+2000x%5E7\" Divide both sides by 2000.
\n" ); document.write( "\"1%2F2+=+x%5E7\"
\n" ); document.write( "\"x+=+0.9057\"Approximately.
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