document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351074>Question 351074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle whose complement is 25 less than half of its supplement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250936 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let angle be x<BR>\n" );
document.write( "xomplement = 90-x<BR>\n" );
document.write( "supplement = 180-x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "90-x = 1/2 * (180-x) -25<BR>\n" );
document.write( "..<BR>\n" );
document.write( "90-x = (180-x -50)/2\r<BR>\n" );
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document.write( "2(90-x)=130-x<BR>\n" );
document.write( "180-2x=130-x<BR>\n" );
document.write( "180-130=2x-x<BR>\n" );
document.write( "50=x the angle\r<BR>\n" );
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document.write( "50 deg. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );