document.write( "Question 351050: If you add the consecutive counting numbers starting with 1, what number will cause the sum to exceed 1000? Explain. \n" ); document.write( "
Algebra.Com's Answer #250927 by edjones(8007)\"\" \"About 
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n=number of terms. a[1]=1st term, a[n]=final term, S=sum of finite arithmetic sequence.
\n" ); document.write( "n/2(a[1]+a[n])=S[n]
\n" ); document.write( "n/2(1+n)>=1000
\n" ); document.write( "n(n+1)>=2000
\n" ); document.write( "n^2+n-2000>=0 Quadratic formula (below)
\n" ); document.write( "n>=44.22
\n" ); document.write( "n=45 the number that will cause the sum to exceed 1,000.
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B-2000+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-2000=8001\".
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\n" ); document.write( " Discriminant d=8001 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+8001+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%281%29%2Bsqrt%28+8001+%29%29%2F2%5C1+=+44.2241545476267\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%281%29-sqrt%28+8001+%29%29%2F2%5C1+=+-45.2241545476267\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B1x%2B-2000\" can be factored:
\n" ); document.write( " \"1x%5E2%2B1x%2B-2000+=+1%28x-44.2241545476267%29%2A%28x--45.2241545476267%29\"
\n" ); document.write( " Again, the answer is: 44.2241545476267, -45.2241545476267.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-2000+%29\"
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