document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=351038>Question 351038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5.	A chemist has one solution that is 15% acid and another solution that is 25% acid. How much of the 15% solution is needed to make 100 L of a solution that is 18% acid?\r<BR>\n" );
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document.write( "a.	45 L			b.  70 L			c.  25 L			d.  30 L </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250907 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 15% acid and another solution that is 25% acid. How much of the 15% solution is needed to make 100 L of a solution that is 18% acid?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.15x + 0.25(100-x) = 0.18*100 L<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "15x + 2500-25x = 1800<BR>\n" );
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document.write( "-10x = -700<BR>\n" );
document.write( "x = 70 L (amt of 15% solution needed for the mixture)<BR>\n" );
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document.write( "100-x = 30L (amt of 25% solution needed for the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( "a. 45 L b. 70 L c. 25 L d. 30 L<BR>\n" );
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