document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39680>Question 39680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help. if the hypotenuse is 20cm and the other sides are x and 2x, how do I calculate what x is?    </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25088 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x~2+(2x)~2=20~2 or 5x~2=20~2 or 5x~2=400 or x~2=400/5 or x~2=80 or x=8.94\r<BR>\n" );
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document.write( "proof 8.94~2+2*8.94~2=20~2 or 80+320=400 or 400=400 </SPAN>\n" );
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