document.write( "Question 350938: A right triangle has a hypoteneuse 11cm long. If the perimeter of the traingle is 25cm, find the lengths of the two other sides. \n" ); document.write( "
Algebra.Com's Answer #250877 by dabanfield@earthlink.net(8)\"\" \"About 
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A right triangle has a hypoteneuse 11cm long. If the perimeter of the traingle is 25cm, find the lengths of the two other sides.\r
\n" ); document.write( "\n" ); document.write( "Let a and b be the lengths of the other two sides. By the Pythagorean Theorem we have:\r
\n" ); document.write( "\n" ); document.write( "1.) 11^2 = a^2 + b^2\r
\n" ); document.write( "\n" ); document.write( "Since the perimeter is 25 we also know a + b + 11 = 25 so:\r
\n" ); document.write( "\n" ); document.write( "a = 25 - 11 - b or
\n" ); document.write( "a = 14 - b\r
\n" ); document.write( "\n" ); document.write( "Substituting 14-b for a in 1.) we have:\r
\n" ); document.write( "\n" ); document.write( "121 = (14-b)^2 + b^2\r
\n" ); document.write( "\n" ); document.write( "121 = 14^2 - 28*b + b^2 + b^2\r
\n" ); document.write( "\n" ); document.write( "121 = 196 - 26*b^2
\n" ); document.write( "26*b^2 = 75
\n" ); document.write( "b^2 = 75/26
\n" ); document.write( "b = sqrt(75/26)
\n" ); document.write( "a = 14 - sqrt(75/26)\r
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