document.write( "Question 350975: A plane took 4 h to fly 2200 km from saskatoon to toronto with a tail wind. Thereturn trip, with a head wind, took 5 h. Find the speed of the plane in still air and the wind speed. \n" ); document.write( "
Algebra.Com's Answer #250873 by dabanfield@earthlink.net(8)![]() ![]() ![]() You can put this solution on YOUR website! A plane took 4 h to fly 2200 km from saskatoon to toronto with a tail wind. Thereturn trip, with a head wind, took 5 h. Find the speed of the plane in still air and the wind speed.\r \n" ); document.write( "\n" ); document.write( "Let w be the wind speed and s be the speed of the plane in still air. \r \n" ); document.write( "\n" ); document.write( "Using the formula distance = rate*time, for the trip with the wind we have:\r \n" ); document.write( "\n" ); document.write( "2200 = (s+w)* 4 or\r \n" ); document.write( "\n" ); document.write( "1.) 2200 = 4*s + 4*w\r \n" ); document.write( "\n" ); document.write( "For the trip against the wind we have:\r \n" ); document.write( "\n" ); document.write( "2200 = (s-w) *5 or\r \n" ); document.write( "\n" ); document.write( "2.) 2200 = 5*s - 5*w\r \n" ); document.write( "\n" ); document.write( "Multiplyng 1.) by 5 and 2.) by 4 we have:\r \n" ); document.write( "\n" ); document.write( "3.) 11000 = 20*s + 20w \n" ); document.write( "4.) 8800 = 20*s - 20*w\r \n" ); document.write( "\n" ); document.write( "Adding the respective sides of 3 and 4 we have:\r \n" ); document.write( "\n" ); document.write( "19800 = 40*s \n" ); document.write( "s = 495\r \n" ); document.write( "\n" ); document.write( "Substitute 495 for s in either 1.) or 2.) above and solve for w.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |