document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350988>Question 350988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm homeschooling my cousin.\r<BR>\n" );
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document.write( "I don't know where to start with this problem: 2(c-3)+5 = 3c-3\r<BR>\n" );
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document.write( "email: chrisen_c@yahoo.com </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250870 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield@earthlink.net><B>dabanfield@earthlink.net(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield@earthlink.net><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.) 2(c-3)+5 = 3c-3\r<BR>\n" );
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document.write( "I assume you are solving for c.\r<BR>\n" );
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document.write( "Expanding the left side of equation 1.) we have\r<BR>\n" );
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document.write( "2.) 2c - 6 + 5 = 3c - 3\r<BR>\n" );
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document.write( "Simplify 2.): \r<BR>\n" );
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document.write( "3.) 2c - 1 = 3c - 3\r<BR>\n" );
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document.write( "Subtract 2c from both sides of 3.):\r<BR>\n" );
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document.write( "4.) 2c - 2c - 1 = 3c - 2c - 3\r<BR>\n" );
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document.write( "Simplify 4.):\r<BR>\n" );
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document.write( "5.) -1 = c - 3\r<BR>\n" );
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document.write( "Add 3 to both sides of equation 5.)\r<BR>\n" );
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document.write( "-1 + 3 = c -3 + 3\r<BR>\n" );
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document.write( "2 = c\r<BR>\n" );
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document.write( " </SPAN>\n" );
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