document.write( "Question 341008: How many four-digit odd integers greater than 6000 can be formed from the digits 0,1,3,5,6 and 8, if no digit can be used more than once? \n" ); document.write( "
Algebra.Com's Answer #250859 by sudhanshu_kmr(1152)\"\" \"About 
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Digits are 0,1,3,5,6,8\r
\n" ); document.write( "\n" ); document.write( " we have to fill four places ABCD, D is unit digit, B is tenth digit and so on..\r
\n" ); document.write( "\n" ); document.write( " number must be greater than 6000 so, \r
\n" ); document.write( "\n" ); document.write( "no. of ways to fill position of A is 2 (6 or 8) \r
\n" ); document.write( "\n" ); document.write( "case 1: when 6 is at A (first digit)
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\n" ); document.write( " no. of ways to fill the position D = 3 (1,3 or 5)
\n" ); document.write( " no. of ways to fill the position B = 4 (only 4 digit remaining)
\n" ); document.write( " no. of ways to fill the position c= 2 (only 3 digit )
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\n" ); document.write( " total no. of ways to form odd integer starting from 6 = 3*4*2= 24\r
\n" ); document.write( "\n" ); document.write( "case 2: when 8 is at A (first digit)
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\n" ); document.write( " similarly, no. of ways to fill the position D = 3
\n" ); document.write( " no. of ways to fill the position B = 4
\n" ); document.write( " no. of ways to fill the position C = 3\r
\n" ); document.write( "\n" ); document.write( " total no. of ways to form odd integer starting from 8 = 3*4*2 =24\r
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\n" ); document.write( "\n" ); document.write( " total no. of four digit odd integers greater than 6000 = 24+24 = 48 \n" ); document.write( "
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