document.write( "Question 350961: A train traveled 80 miles from city A to city B and returned the same distance in a total time of 6 hours. If the train traveled 20 mph slower on the return trip, how fast did the train travel in each direction? \n" ); document.write( "
Algebra.Com's Answer #250858 by stanbon(75887)\"\" \"About 
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A train traveled 80 miles from city A to city B and returned the same distance in a total time of 6 hours. If the train traveled 20 mph slower on the return trip, how fast did the train travel in each direction?
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\n" ); document.write( "A to B DATA:
\n" ); document.write( "distance = 80 miles ; rate = x mph ; time = 80/x hrs
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\n" ); document.write( "B to A DATA:
\n" ); document.write( "distance = 80 miles ; rate = x-20 mph ; time = 80/(x-20) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 6 hrs
\n" ); document.write( "80/x + 80/(x-20) = 6
\n" ); document.write( "160x - 1600 = 6x(x-20)
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\n" ); document.write( "160x - 1600 = 6x^2 - 120x
\n" ); document.write( "6x^2 -280x + 1600 = 0
\n" ); document.write( "3x^2 - 140x + 800 = 0
\n" ); document.write( "(3x-20)(x-40) = 0
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\n" ); document.write( "Realistic Answer:
\n" ); document.write( "x = 40 mph (rate from A to B)
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\n" ); document.write( "x-20 = 20 mph (rate from B to A)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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