document.write( "Question 342414: In how many ways can 12 poeple be divided into 3 groups of 4 persons(in each group)? \n" ); document.write( "
Algebra.Com's Answer #250855 by sudhanshu_kmr(1152)\"\" \"About 
You can put this solution on YOUR website!
12 people and 3 groups of 4\r
\n" ); document.write( "\n" ); document.write( "no. of ways to select 4 people from 12 for first group = 12C4 = 495 \r
\n" ); document.write( "\n" ); document.write( " no. of ways to select 4 people from remaining 8 for second group = 8C4 = 70\r
\n" ); document.write( "\n" ); document.write( "no. of ways to select 4 people from 4 for third group = 4C4 = 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " total no. of ways to select people for group = 495 * 70 * 1 / 3! = 34650 /6
\n" ); document.write( "
\n" ); document.write( " = 5775\r
\n" ); document.write( "\n" ); document.write( " Here we divide by 3! here position or identification of groups does not matter.
\n" ); document.write( " All groups have equal identity, arrangement of group does not matter. \r
\n" ); document.write( "\n" ); document.write( " For example, if there are 3 groups having names G1, G2, G3 then there is no need to divide by 3!. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Sometimes there may be typing mistake in solution of a problem, so please ignore it. Understand the concept and try the problem yourself. \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
\n" );