document.write( "Question 349633: 5 women and 6 men are on a softball team. Two of them are brothers. How many ways can you form a committee of 2 women and 3 men if you keep the brothers together, either both on the committee or both off the committee? What is the probability that the committee will have 2 women and 3 men and that the brothers will be together, either both on the committee or both off the committee?\r
\n" );
document.write( "\n" );
document.write( "I tried 5C3 x 5C2 for the first part and (5C3 x 5C2)11C5 for the second part but I don't think it's right. Any help would be greatly appreciated.\r
\n" );
document.write( "\n" );
document.write( "Thanks \n" );
document.write( "
Algebra.Com's Answer #250816 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are 5 women and 6 men. We have to select 2 women and 3 men. \r \n" ); document.write( "\n" ); document.write( "First case: both brothers are in committee \n" ); document.write( "as both are in committee, now we have to choose 1 from remaining 4 men \n" ); document.write( "no. of ways = 5C2 * 4C1 = 10 * 4 = 40\r \n" ); document.write( "\n" ); document.write( "Second case : both are not in committee \n" ); document.write( " now we have to choose all 3 men from remaining 4 \r \n" ); document.write( "\n" ); document.write( " no. of ways = 5C2 * 4C3 = 10 * 4 = 40\r \n" ); document.write( "\n" ); document.write( " total no. of ways = 40 + 40 = 80 \r \n" ); document.write( "\n" ); document.write( "Your question related to probability is not cleared... \n" ); document.write( "please resubmit \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |