document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350735>Question 350735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the hypotenuse of a right triangle is 30 cm long and one leg is twice as long as the other, how long are the legs of the triangle?\r<BR>\n" );
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document.write( "I think I'm suppose to set it up 30^2=a^2 +2b^2, but I'm not sure.  And if it is, I'm not sure how to solve for both a and b. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250757 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if one leg is x<BR>\n" );
document.write( "the other leg will be 2x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x^2+(2x)^2=30^2<BR>\n" );
document.write( "x^2+4x^2=900<BR>\n" );
document.write( "5x^2=900<BR>\n" );
document.write( "x^2=900/5<BR>\n" );
document.write( "x^2=180<BR>\n" );
document.write( "x= sqrt 180 = 13.4 cm<BR>\n" );
document.write( "other leg will be 2*13.4 = 26.8 cm </SPAN>\n" );
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