document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350762>Question 350762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 square root of 13 + 7 square root of 13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250739 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (~3:(13+7))(~(13))     ~ symbol = square root\r<BR>\n" );
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document.write( "Add 7 to 13 to get 20.<BR>\n" );
document.write( "(~3:(20))(~(13))\r<BR>\n" );
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document.write( "Multiply ~3:(20) by ~(13) to get ~3:(20)~(13).<BR>\n" );
document.write( "(~3:(20)~(13))\r<BR>\n" );
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document.write( "Remove the parentheses around the expression ~3:(20)~(13).<BR>\n" );
document.write( "~3:(20)~(13)\r<BR>\n" );
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document.write( "The approximate value of (~3:(13+7))(~(13)) is 2.71.<BR>\n" );
document.write( "2.71 </SPAN>\n" );
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