document.write( "Question 350758: The length of a rectangle is five times its width.
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document.write( "If the area of the rectangle is 405ft, find its perimeter. \n" );
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Algebra.Com's Answer #250736 by haileytucki(390)![]() ![]() You can put this solution on YOUR website! The length of a rectangle is five times its width. \n" ); document.write( "If the area of the rectangle is 405ft, find its perimeter.\r \n" ); document.write( "\n" ); document.write( "l = 2w \r \n" ); document.write( "\n" ); document.write( "We know the area is 405 so, \n" ); document.write( "lw = w(w) = 2w^2 = 405\r \n" ); document.write( "\n" ); document.write( "5w^(2)=405\r \n" ); document.write( "\n" ); document.write( "Divide each term in the equation by 5. \n" ); document.write( "(5w^(2))/(5)=(405)/(5)\r \n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common factors. \n" ); document.write( "w^(2)=(405)/(5)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, The perimeter is the sum of the lengths of all four sides.\r \n" ); document.write( "\n" ); document.write( "2L + 2W= \n" ); document.write( "18 +90= 108 perimeter\r \n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by simplifying each term. \n" ); document.write( "w^(2)=81\r \n" ); document.write( "\n" ); document.write( "Take the square root of both sides of the equation to eliminate the exponent on the left-hand side. \n" ); document.write( "w=\~(81)\r \n" ); document.write( "\n" ); document.write( "Pull all perfect square roots out from under the radical. In this case, remove the 9 because it is a perfect square. \n" ); document.write( "w=\9\r \n" ); document.write( "\n" ); document.write( "First, substitute in the + portion of the \ to find the first solution. \n" ); document.write( "w=9\r \n" ); document.write( "\n" ); document.write( "So, simply, \n" ); document.write( " 9 ft is the width \n" ); document.write( "and 45 is the length (45 is the length because it is 5 times the width, which is 9)\r \n" ); document.write( "\n" ); document.write( "Proof:\r \n" ); document.write( "\n" ); document.write( "45*9\r \n" ); document.write( "\n" ); document.write( "Multiply 45 by 9 to get 405. \n" ); document.write( "405 \n" ); document.write( " |