document.write( "Question 350758: The length of a rectangle is five times its width.
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document.write( "If the area of the rectangle is 405ft, find its perimeter. \n" );
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Algebra.Com's Answer #250733 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is five times its width. \n" ); document.write( "If the area of the rectangle is 405ft, find its perimeter. \n" ); document.write( "-------------- \n" ); document.write( "L = 5W \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "Area = LW \n" ); document.write( "405 = (5W)W \n" ); document.write( "81= W^2 \n" ); document.write( "W = 9 \n" ); document.write( "--------------------- \n" ); document.write( "L = 5W = 45 \n" ); document.write( "====================== \n" ); document.write( "Perimeter = 2(L+W) \n" ); document.write( "P = 2(45+9) \n" ); document.write( "P = 2(54) \n" ); document.write( "P = 108 \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |