document.write( "Question 350758: The length of a rectangle is five times its width.
\n" ); document.write( "If the area of the rectangle is 405ft, find its perimeter.
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Algebra.Com's Answer #250733 by stanbon(75887)\"\" \"About 
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The length of a rectangle is five times its width.
\n" ); document.write( "If the area of the rectangle is 405ft, find its perimeter.
\n" ); document.write( "--------------
\n" ); document.write( "L = 5W
\n" ); document.write( "---
\n" ); document.write( "Equation:
\n" ); document.write( "Area = LW
\n" ); document.write( "405 = (5W)W
\n" ); document.write( "81= W^2
\n" ); document.write( "W = 9
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\n" ); document.write( "L = 5W = 45
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\n" ); document.write( "Perimeter = 2(L+W)
\n" ); document.write( "P = 2(45+9)
\n" ); document.write( "P = 2(54)
\n" ); document.write( "P = 108
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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