document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350686>Question 350686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How To Solve This lnequalities r+2r<30;9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250724 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the ; in your problem? Is that a typo?<BR>\n" );
document.write( "If not I worked the problem correctly as:\r<BR>\n" );
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document.write( "r+2r<309\r<BR>\n" );
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document.write( "Since r and 2r are like terms, add 2r to r to get 3r.<BR>\n" );
document.write( "3r<309\r<BR>\n" );
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document.write( "Divide each term in the inequality by 3.<BR>\n" );
document.write( "(3r)/(3)<(309)/(3)\r<BR>\n" );
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document.write( "Simplify the left-hand side of the inequality by canceling the common factors.<BR>\n" );
document.write( "r<(309)/(3)\r<BR>\n" );
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document.write( "Simplify the right-hand side of the inequality by simplifying each term.<BR>\n" );
document.write( "r<103 </SPAN>\n" );
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