document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350731>Question 350731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat travels 60 km upstream (against the current) in 5 hours.  the boat travels the same distance downstream in 3 hours.  What is the rate of the boat in still water?  What is the rate of the current?  \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250713 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let rate of boat in still water = x<BR>\n" );
document.write( "let rate of current be y<BR>\n" );
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document.write( "Speed = distance / time<BR>\n" );
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document.write( "speed upstream = x-y<BR>\n" );
document.write( "speed downstream = x+y<BR>\n" );
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document.write( "time upstream = 60/x-y =5<BR>\n" );
document.write( "60/5 = x-y<BR>\n" );
document.write( "x-y =12...............1<BR>\n" );
document.write( "time downstream = 60/x+y = 3<BR>\n" );
document.write( "x+y =20...............2<BR>\n" );
document.write( "add equation 1 & 2<BR>\n" );
document.write( "2x = 12+20<BR>\n" );
document.write( "2x = 32<BR>\n" );
document.write( "x=16 mph rate of boat.<BR>\n" );
document.write( "x-y =12<BR>\n" );
document.write( "so y=4 rate of current </SPAN>\n" );
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