document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350720>Question 350720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor by grouping -  x^3+6x^2-2x-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250706 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  x^3+6x^2-2x-12\r<BR>\n" );
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document.write( "x^3 + 6x^2 = group 1\r<BR>\n" );
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document.write( "-2x - 12 = group 2\r<BR>\n" );
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document.write( "Factor each group individually.\r<BR>\n" );
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document.write( "x^3 + 6x^2 becomes x^2(x + 6)\r<BR>\n" );
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document.write( "-2x - 12 becomes -2(x + 6)\r<BR>\n" );
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document.write( "(x^2 - 2)(x + 6)\r<BR>\n" );
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