document.write( "Question 5028: there were 429 people nat a play. admission was $1 for adults and $.75 for children. the receits were $372.50. How many adults and how many children attended the play? \n" ); document.write( "
Algebra.Com's Answer #2507 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let A = # of adults. \n" ); document.write( "Let C = # of children.\r \n" ); document.write( "\n" ); document.write( "A + C = 429 Rewrite as: C = 429-A and substitute into the equation below: \n" ); document.write( "($1.00)A + ($0.75)C = $372.50\r \n" ); document.write( "\n" ); document.write( "($1.00)A + ($0.75)((429-A) = $372.50 Simplify and solve for A \n" ); document.write( "($1.00)A + $321.75-$0.75A = $372.50 Subtract $321.75 from both sides. \n" ); document.write( "$1.00A - $0.75A = $50.75 \n" ); document.write( "$0.25A = $50.75 Divide both sides by $0.25 \n" ); document.write( "A = 203 There were 203 adults in attendance. \n" ); document.write( "C = 429-A \n" ); document.write( "C = 429-203 \n" ); document.write( "C = 226 There were 226 children in attendance.\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "203($1.00) + 226($0.75) = $203.00 + $169.50 = $372.50 \n" ); document.write( " \n" ); document.write( " |