document.write( "Question 350690: can you show me how to solve this equation 3p over 5 plus 2 over 3 equals p plus 4 over 3. \n" ); document.write( "
Algebra.Com's Answer #250683 by jjordan95(63)\"\" \"About 
You can put this solution on YOUR website!
\"3p%2F5%2B2%2F3=p%2B4%2F3\" <--- Original equation\r
\n" ); document.write( "\n" ); document.write( "First thing you need to do is move all of the \"p-terms\" to one side. I will move them to the left. Then you can solve for \"p\".\r
\n" ); document.write( "\n" ); document.write( "\"3p%2F5=p%2B4%2F3-2%2F3\" <--- Move 2/3 to the right by subtracting it from both sides.
\n" ); document.write( "\"3p=5%28p%2B2%2F3%29\" <--- Multiply both sides by 5 to get rid of the fraction on the left side. Simplify like-terms (common denominators)
\n" ); document.write( "\"3p=5p%2B10%2F3\" <--- Distribute the 5
\n" ); document.write( "\"3p-5p=10%2F3\" <--- Move all p-terms to the left side. (Subtract 5p from both sides.)
\n" ); document.write( "\"-2p=10%2F3\" <--- Simplify left side.
\n" ); document.write( "\"p=%2810%2F3%29%2A%28-%281%2F2%29%29\" <--- Divide both sides by -2. (Which is the same as multiplying by its reciprocal which is \"-%281%2F2%29\"
\n" ); document.write( "\"p=10%2F6\" <--- Solve for P
\n" ); document.write( "\"highlight%28p=5%2F3%29\" <--- Simplified version of the answer.\r
\n" ); document.write( "\n" ); document.write( "Here is the alternate solution - depending on how the equation is actually written.
\n" ); document.write( "
\n" );