document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350616>Question 350616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 6 more yards than the width. If the perimiter is 184 yards, what are the length and width<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250610 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "*Note: Let x be the width.  Then (x+6) is the length.<BR>\n" );
document.write( "In general, the Perimeter is 2w + 2l<BR>\n" );
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document.write( "2x + 2(x+6) = 184yds<BR>\n" );
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document.write( "simplify and solve<BR>\n" );
document.write( "4x + 12 = 184yds<BR>\n" );
document.write( "4x = 172yds<BR>\n" );
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document.write( "x = 43yds   (the width)<BR>\n" );
document.write( "length is 49yds  <BR>\n" );
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document.write( "check your answer<BR>\n" );
document.write( "86 + 2*49 = 184 </SPAN>\n" );
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