document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350580>Question 350580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a triangle is 165 square feet.If the height is 4 more than the base, find the length of the height and base of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250584 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of triangle = 1/2*base * height.<BR>\n" );
document.write( "Area = 165 sq.ft<BR>\n" );
document.write( "let base be x<BR>\n" );
document.write( "height = x+4\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "A= 1/2 * x*(x+4)<BR>\n" );
document.write( "1/2 *(x^2+4x)=165<BR>\n" );
document.write( "x^2+4x = 330\r<BR>\n" );
document.write( "\n" );
document.write( "x^2+4x-330=0<BR>\n" );
document.write( "solve for x using quadratic formula<BR>\n" );
document.write( "b^2-4ac= 16+1320=346<BR>\n" );
document.write( "(-4+sqrt(1336)) /2 <BR>\n" );
document.write( "=16.27 base<BR>\n" );
document.write( "height = 20.27 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );