document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350523>Question 350523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 14. Six times the first number minus three times the second number is 3.  Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250545 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one number be x<BR>\n" );
document.write( "the other number will be 14-x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "6x-3(14-x)=3<BR>\n" );
document.write( "6x-42+3x=3<BR>\n" );
document.write( "6x+3x=42+3<BR>\n" );
document.write( "9x=45\r<BR>\n" );
document.write( "\n" );
document.write( "/9<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "other number = 9  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );