document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350452>Question 350452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 18a^2+24ad+8d^2<BR>\n" );
document.write( "factor the equation<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250527 by </B><A HREF=/tutors/aboutme.mpl?userid=kicker1238><B>kicker1238(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kicker1238><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18a^2+24ad+8d^2\r<BR>\n" );
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document.write( "Find common factor that divides them equally, in this case 2.\r<BR>\n" );
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document.write( "2(9a^2+12ad+4d^2)<BR>\n" );
document.write( "Ignore the 2 for now we'll put it in later.\r<BR>\n" );
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document.write( "9a^2+12ad+4d^2\r<BR>\n" );
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document.write( "3x3=9<BR>\n" );
document.write( "2x2=4<BR>\n" );
document.write( "Add them together you get Cross multiply 3x2=6 and the other 3x2=6<BR>\n" );
document.write( "6+6=12, there's your b, 3x3=9 is your a 2x2=4 is your c.\r<BR>\n" );
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document.write( "(3a^2+2d)(3a^2+2d)\r<BR>\n" );
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document.write( "Plug the 2 back in<BR>\n" );
document.write( "Final Answer:<BR>\n" );
document.write( "2(3a^2d)(3a^2+2d) </SPAN>\n" );
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