document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5024>Question 5024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a vending machine takes only nickels and dimes. there are 5 times as many dimes as nickels in the machine. the face value of the coins is $4.40. how many of each coin are in the machine? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2505 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let D = # of dimes ($0.10)<BR>\n" );
document.write( "Let N = # of nickels ($0.05)\r<BR>\n" );
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document.write( "There are 5 time as many dimes as nickels, so: D = 5N Substitute this into the eqation below.<BR>\n" );
document.write( "The total value of the coins is, so: ($0.10)D + ($0.05)N = $4.40\r<BR>\n" );
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document.write( "Now you have two equations and two unknowns.  You can solve the problem.\r<BR>\n" );
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document.write( "($0.10)(5N) + ($0.05)N = $4.40  Simplify.<BR>\n" );
document.write( "($0.50)N + ($0.05)N = $4.40<BR>\n" );
document.write( "($0.55)N = $4.40  Divide both sides by ($0.55)<BR>\n" );
document.write( "N = 8  There are 8 nickels.<BR>\n" );
document.write( "D = 5N<BR>\n" );
document.write( "D = 5(8)<BR>\n" );
document.write( "D = 40 There are 40 dimes.\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "($0.05)(8) + $).10)(40) = $0.40 + $4.00 = $4.40 \r<BR>\n" );
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document.write( " </SPAN>\n" );
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