document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350442>Question 350442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two surveyors with two-way radios leave the same point at 9:00 A.M., one walking due south at 2 mi/hr and the other due west at 4 mi/hr . How long can they communicate with one another if each radio has a maximum range of 4 miles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250499 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance  of west bound = 4*t = 4t miles t = time<BR>\n" );
document.write( "distance of south bound = 2*t = 2t miles<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Their positions after time t form a right triangle with the starting point. <BR>\n" );
document.write( "8^2 = (4t)^2+(2t)^2<BR>\n" );
document.write( "64= 16t^2+4t^2<BR>\n" );
document.write( "64=20t^2<BR>\n" );
document.write( "64/20 = t^2<BR>\n" );
document.write( "16/5 = t^2<BR>\n" );
document.write( "take square root<BR>\n" );
document.write( "4/sqrt5 = t<BR>\n" );
document.write( "t= 1.78 hours </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );