document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350337>Question 350337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measures of the three angles of a triangle if the measure of the second angle is 10 degrees greater than the first angle and the measure of the third angle is 30 degrees less than twice the measure of the first angle. Use the equation with a variable properly defined.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250478 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250478\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of the angles of a triangle is always 180 degrees.\r<BR>\n" );
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document.write( "first angle = A\r<BR>\n" );
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document.write( "second angle = A + 30\r<BR>\n" );
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document.write( "third angle = 2A - 30\r<BR>\n" );
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document.write( "A + (A + 30) + (2A - 30) = 180\r<BR>\n" );
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document.write( "Can you take it from here? </SPAN>\n" );
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