document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350308>Question 350308</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The ratio of Aldo's cycling speed to Jose cycling speed is 6:5. Jose leaves school at 3pm and Aldo leaves at 3:10pm. By 3:30pm Aldo is only 2 km behind Jose. How fast is each cycling?\r<BR>\n" );
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document.write( "rate=distance/time so Aldo is traveling at 6x and Jose is traveling at 5x<BR>\n" );
document.write( "6x(1/3)-2=5x(1/2)\r<BR>\n" );
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document.write( "I'm not sure if I am on the right track. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250465 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> pretty good\r<BR>\n" );
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document.write( "since Aldo is 2km BEHIND Jose , you need to ADD (not subtract) the 2 to make the distances equal </SPAN>\n" );
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