document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350266>Question 350266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An insect population P in a certain area fluctuates with the seasons. It is estimated that P=17,000+4500sin pi(t)/52, where t is given in weeks. Determine the number of weeks it would take for the population to initially reach 20,000. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250365 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An insect population P in a certain area fluctuates with the seasons. <BR>\n" );
document.write( "It is estimated that P=17,000+4500sin pi(t)/52, where t is given in weeks. Determine the number of weeks it would take for the population to initially reach 20,000.<BR>\n" );
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document.write( "20,000 = 17,000+4500sin pi(t)/52<BR>\n" );
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document.write( "3000 = 4500*sin(pi*t/52)<BR>\n" );
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document.write( "1/15 = sin(pi*t/52)<BR>\n" );
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document.write( "(pi*t/52) = sin^-1(1/15)<BR>\n" );
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document.write( "(pi/52)t = 0.0667<BR>\n" );
document.write( "pi*t = 3.4692<BR>\n" );
document.write( "t = 1.1043 weeks<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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