document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350246>Question 350246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.a rectangular field 70m long and 50m wide has a path of uniform width around it . if the area of the path is 1024 sq.cm.find the width of the path \r<BR>\n" );
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document.write( "2.The base and height of a triangle are (x+3) and (2x-5)cm respectively if the area of the triangle is 20 sq.cm find x\r<BR>\n" );
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document.write( "3.The length of a rectangle is 5cm longer than its width and its area is 66 sq.cm find the perimeter of the rectangle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250356 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.a rectangular field 70m long and 50m wide has a path of uniform width around it . if the area of the path is 1024 sq.m.find the width of the path<BR>\n" );
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document.write( "Draw the picture of a rectangle inside a rectangle.<BR>\n" );
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document.write( "The area of the inner rectangle is 70*50 = 3500 sq. meters<BR>\n" );
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document.write( "Area of the outer rectangle = (70+2x)(50+2x) = 4X^2 + 240x + 3500<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Outer area - Inner area = 4x^2+ 240x = 1024<BR>\n" );
document.write( "x^2+60x-256 = 0<BR>\n" );
document.write( "(x-4)(x+64) = 0<BR>\n" );
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document.write( "Positive Solution:<BR>\n" );
document.write( "x = 4 meters.<BR>\n" );
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document.write( "  <BR>\n" );
document.write( "2.The base and height of a triangle are (x+3) and (2x-5)cm respectively if the area of the triangle is 20 sq.cm find x<BR>\n" );
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document.write( "Area = (1/2)(base)(height)<BR>\n" );
document.write( "20 cm^2 = (1/2)(x+3)(2x-5)<BR>\n" );
document.write( "40 = 2x^2+x-15<BR>\n" );
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document.write( "2x^2+x-55 = 0<BR>\n" );
document.write( "(x-5)(2x+11) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 5<BR>\n" );
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document.write( "base = x+3 = 9 cm<BR>\n" );
document.write( "height = 2x-5 = 5 cm<BR>\n" );
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document.write( "3.The length of a rectangle is 5cm longer than its width and its area is 66 sq.cm find the perimeter of the rectangle.<BR>\n" );
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document.write( "Let width = x<BR>\n" );
document.write( "The length = x+5<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x(x+5) = 66<BR>\n" );
document.write( "x^2+5x-66 = 0<BR>\n" );
document.write( "(x+11)(x-6) = 0<BR>\n" );
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document.write( "Positive Solution:<BR>\n" );
document.write( "x = 6 cm<BR>\n" );
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document.write( "Perimeter = 2(width + length)<BR>\n" );
document.write( "P = 2(6 + 11)<BR>\n" );
document.write( "P = 2(17)<BR>\n" );
document.write( "Perimeter = 34 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== <BR>\n" );
document.write( " </SPAN>\n" );
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