document.write( "Question 350207: forty ounces of a 30% gold alloy are mixed with 60oz of a 20% gold alloy. Find the percent concentration of the resulting gold alloy \n" ); document.write( "
Algebra.Com's Answer #250318 by Fombitz(32388)\"\" \"About 
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Let X be the new concentration,
\n" ); document.write( "\"30%2840%29%2B20%2860%29=X%28100%29\"
\n" ); document.write( "\"1200%2B1200=100X\"
\n" ); document.write( "\"X=24\"
\n" ); document.write( "The new alloy is 24% copper.
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