document.write( "Question 350161: Twenty mp3 players are produced in a production run. The probability of producing a defective mp3 player is 3%. What is the expected number of NON-defective mp3 players in the production run? What is the probability that at least 17 mp3 players are NON-defective? \n" ); document.write( "
Algebra.Com's Answer #250285 by edjones(8007)\"\" \"About 
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20 * .97 = 19.4 the expected number of NON-defective mp3 players in the production run.
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\n" ); document.write( "Let x=.97 and y=.03
\n" ); document.write( "Expand (x+y)^20
\n" ); document.write( "x^20+20x^19y+190x^18y^2+1140x^17y^3=.9973 probability that at least 17 mp3 players are NON-defective
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