document.write( "Question 350161: Twenty mp3 players are produced in a production run. The probability of producing a defective mp3 player is 3%. What is the expected number of NON-defective mp3 players in the production run? What is the probability that at least 17 mp3 players are NON-defective? \n" ); document.write( "
Algebra.Com's Answer #250285 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 20 * .97 = 19.4 the expected number of NON-defective mp3 players in the production run. \n" ); document.write( ". \n" ); document.write( "Let x=.97 and y=.03 \n" ); document.write( "Expand (x+y)^20 \n" ); document.write( "x^20+20x^19y+190x^18y^2+1140x^17y^3=.9973 probability that at least 17 mp3 players are NON-defective \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |