document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350102>Question 350102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the complement of an angle is 6° less than one-third of its supplement, find the measure of the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250219 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let angle be x<BR>\n" );
document.write( "complement = 90-x<BR>\n" );
document.write( "supplement = 180-x<BR>\n" );
document.write( "....<BR>\n" );
document.write( "90-x = 1/3 (180-x)-6<BR>\n" );
document.write( "3(90-x)=180-x\r<BR>\n" );
document.write( "\n" );
document.write( "270-3x=180-x<BR>\n" );
document.write( "270-180+6=3x-x<BR>\n" );
document.write( "96=2x<BR>\n" );
document.write( "x=48<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );