document.write( "Question 349945: The sum of the digits in a two-digit number is 8. When the digits are reversed, the new number is 18 less than the original number. Set up the equations you would need to solve this problem – do not solve it please. \n" ); document.write( "
Algebra.Com's Answer #250200 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Let x = the 10s digit, Let y = the units \n" ); document.write( "then \n" ); document.write( "10x + y = \"the original number\" \n" ); document.write( "10y + x = the \"new number\" \n" ); document.write( ": \n" ); document.write( "Just write an equation for what it says: \n" ); document.write( ": \n" ); document.write( "The sum of the digits in a two-digit number is 8. \n" ); document.write( "x + y = 8 \n" ); document.write( ": \n" ); document.write( "When the digits are reversed, the new number is 18 less than the original number. \n" ); document.write( "10y + x = 10x + y - 18 \n" ); document.write( "you can simplify, combine like terms \n" ); document.write( "10y - y = 10x - x - 18 \n" ); document.write( "9y = 9x - 18 \n" ); document.write( "Divide by 9 \n" ); document.write( "y = x - 2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |