document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350083>Question 350083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the second side of a triangle is 2dm less than twice the first side and the third side is 4dm less than twice the second side. how long is each side if the perimeter of the triangle is 18dm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250191 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let first side be x dm<BR>\n" );
document.write( "second side = 2x-2<BR>\n" );
document.write( "third side =2(2x-2)-4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+2x-2+4x-4-4 =18<BR>\n" );
document.write( "7x-10=18<BR>\n" );
document.write( "7x = 28<BR>\n" );
document.write( "x= 4 first side<BR>\n" );
document.write( "2x-2 = 8-2 =  6 second side<BR>\n" );
document.write( "third side = 2(2*4-2)-4=8<BR>\n" );
document.write( "..<BR>\n" );
document.write( "4+6+8 =18dm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );