document.write( "Question 350072: Karen saves her change and has dimes, nickels, and pennies totaling $4.52. If there is 1 more dime than three times the number of nickels and 10 more pennies than nickels, how many of each type of coin are there?\r
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document.write( "I start the formula like this:\r
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document.write( "(3x+10)+(x+10)+x=4.52\r
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document.write( "x is the number of nickels.
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document.write( "3x+10 is 3 times the number of nickels plus one dime.
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document.write( "x+10 is 10 more than the number of pennies.
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document.write( "x is the number of nickels\r
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document.write( "I've tried to solve this by changing around the decimals n' such but the only time the number comes out even is by dividing both sides by 4 (4x=432--4x/4=432/4) Otherwise they come out with decimals equaling 3-4 places.\r
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document.write( "Thank you so much :)
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document.write( "Any help is appreciated :) \n" );
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Algebra.Com's Answer #250189 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Karen saves her change and has dimes, nickels, and pennies totaling $4.52. If there is 1 more dime than three times the number of nickels and 10 more pennies than nickels, how many of each type of coin are there?\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "let nickels = x \n" ); document.write( "pennies = x+10 \n" ); document.write( "dimes= 3x+1 \n" ); document.write( "... \n" ); document.write( "5x+x+10+10(3x+1)=452 \n" ); document.write( "5x+x+10+30x+10=452 \n" ); document.write( "36x+20=452 \n" ); document.write( "36x=452-20 \n" ); document.write( "36x=432 \n" ); document.write( "/36 \n" ); document.write( "x= 432/36 \n" ); document.write( "x=12 the number of nickels \n" ); document.write( "pennies = 10+12 = 22 \n" ); document.write( "dimes =3x+1 = 37 \n" ); document.write( "... \n" ); document.write( "CHECK \n" ); document.write( "12*5 + 22*1+37*10= 452 \n" ); document.write( " \n" ); document.write( " |