document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350022>Question 350022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help for this system , can you please help me? I will really appreciate it<BR>\n" );
document.write( " 1/x + 1/y =6<BR>\n" );
document.write( " 2x+y=3 <BR>\n" );
document.write( "I've tried to subtract y and then to solve the system but didnt work .then I 've tried to notate 1/x with a and 1/y with b, but I got stack because I didn't know what should I do with the second equation .<BR>\n" );
document.write( "thank you for your help.<BR>\n" );
document.write( "daniela   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250176 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> from 2nd equation ___ y = 3-2x\r<BR>\n" );
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document.write( "substituting ___ (1/x) + [1/(3-2x)] = 6\r<BR>\n" );
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document.write( "3-2x + x = 6(x)(3-2x) ___ 3-2x + x = 18x - 12x^2\r<BR>\n" );
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document.write( "0 = 12x^2 - 19x + 3\r<BR>\n" );
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document.write( "use quadratic formula to find the x-values , then substitute to find the corresponding y-values </SPAN>\n" );
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