document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=350024>Question 350024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that passes through the pair of points. Write your answer in standard form. \r<BR>\n" );
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document.write( "(1/4, -1/3) (-1/4, -3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250175 by </B><A HREF=/tutors/aboutme.mpl?userid=cdmcg><B>cdmcg(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cdmcg><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   use the formula y2-y1=m(x2-x1)\r<BR>\n" );
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document.write( "-3+1/3=m(-1/4-1/4)<BR>\n" );
document.write( "-8/3=m(-1/2)<BR>\n" );
document.write( "m=16/3\r<BR>\n" );
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document.write( "standard formula ax+by=c\r<BR>\n" );
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document.write( "16/3=(y+3):(x+1/4)  => 3(y+3)=16(x+1/4) 3y+9=16x+4 =>-16x+3y=-5  =>16x-3y=5<BR>\n" );
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