document.write( "Question 350028: The speed of the freight train is 23 mph slower than that of a passenger train. The freight train travels 250 miles in the same time it takes the passenger train to travel 450 miles. Find the speed of the passenger train. \n" ); document.write( "
Algebra.Com's Answer #250172 by mananth(16946)![]() ![]() You can put this solution on YOUR website! freight train speed = x mph \n" ); document.write( "passenger train speed = x+23 mph \n" ); document.write( ".. \n" ); document.write( "distance by freight train = 250 miles \n" ); document.write( "distrance by passenger = 450 miles. \n" ); document.write( ".. \n" ); document.write( "Time taken by both = same \n" ); document.write( ".. \n" ); document.write( "250/x = 450/(x+23) \n" ); document.write( "250(x+23)=450x \n" ); document.write( "250x+5750=450x \n" ); document.write( "450x-250x=5750 \n" ); document.write( "200x = 5750 \n" ); document.write( "/200 \n" ); document.write( "x= 5750/200 \n" ); document.write( "x=28.75 mph freight train \n" ); document.write( "passenger train speed = 28.75+23=51.75mph\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |