document.write( "Question 349983: the perimeter of a college basketball court is 96m and the lenght is 14m more than the width. what are the dimensions. \n" ); document.write( "
Algebra.Com's Answer #250165 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let width =x \n" ); document.write( "length = x+14 \n" ); document.write( ".. \n" ); document.write( "Perimeter = 96 = 2*(L+W) \n" ); document.write( "96=2*(X+X+14) \n" ); document.write( "96=2*(2x+14) \n" ); document.write( "96=4x+28 \n" ); document.write( "96-28=4x \n" ); document.write( "68=4x \n" ); document.write( "/4 \n" ); document.write( "68/4=x \n" ); document.write( "17=x the width \n" ); document.write( "length = 17+14= 31m \n" ); document.write( "... \n" ); document.write( "CHECK \n" ); document.write( "17+17+31+31=96 \n" ); document.write( " |