document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349990>Question 349990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Denver Chemical Company wants to increase its 10% peroxide solution to a 28% solution by adding 100% peroxide. If Denver has 500 gallons its original 10% peroxide, how much pure peroxide must it add to obtain the new mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250161 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10% peroxide solution 500 gallons<BR>\n" );
document.write( "100%   let it be x gallons<BR>\n" );
document.write( "to a 28% solution total = 500 +x gallons<BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.1*500 +x = 0.28(500+x)<BR>\n" );
document.write( "50+x =140+0.28x<BR>\n" );
document.write( "x-0.28x=140-50<BR>\n" );
document.write( "0.72x=90<BR>\n" );
document.write( "/0.72<BR>\n" );
document.write( "x=90/0.72<BR>\n" );
document.write( "125 gallons </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );