document.write( "Question 350003: what is the equation of the parabola who has a focus of (3,-5) and the equation of the directrix is y=-2? \n" ); document.write( "
Algebra.Com's Answer #250154 by alanc(27)\"\" \"About 
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Refer to the standard form for a parabola: (x-h)^2 = 4a*(y-k) vertex of parabola is at (h,k) focus is at (h, k + a).
\n" ); document.write( "directrix at y= k - a\r
\n" ); document.write( "\n" ); document.write( "we have y = -2 = k - a and -5 = k + a, with h = 3\r
\n" ); document.write( "\n" ); document.write( "-2 = k - a
\n" ); document.write( "-5 = k + a\r
\n" ); document.write( "\n" ); document.write( "-7 = 2k\r
\n" ); document.write( "\n" ); document.write( "k = -7/2\r
\n" ); document.write( "\n" ); document.write( "vertex at (3, -7/2)\r
\n" ); document.write( "\n" ); document.write( "a = -5 - k = -5 - (-7/2) = -3/2\r
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\n" ); document.write( "\n" ); document.write( "equation is : (x -3)^2 = 4*(-3/2)*(y - (-7/2))\r
\n" ); document.write( "\n" ); document.write( "Equation: (x-3)^2 = -6(y + 7/2)\r
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