document.write( "Question 349994: Zelma is eighteen years older than her son. She was three times as oldas he was one year ago. How old are they now?\r
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Algebra.Com's Answer #250149 by mananth(16946)\"\" \"About 
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let son be x years
\n" ); document.write( "Zelma = x+18
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\n" ); document.write( "1 year ago
\n" ); document.write( "son was x-1 years
\n" ); document.write( "Zelma was x+18-1 = x+17 years
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\n" ); document.write( "x+17 = 3(x-1)
\n" ); document.write( "x+17 = 3x-3
\n" ); document.write( "3x-x =17+3
\n" ); document.write( "2x=20
\n" ); document.write( "/2
\n" ); document.write( "x=10 son's age
\n" ); document.write( "Zelma = 10 + 18 = 28 years.
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