document.write( "Question 349973: Solve each system by the substitution method\r
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document.write( "a) 2x - y = 4
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document.write( " 2x - y = 3\r
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document.write( "b) x + 3y = 2
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document.write( " -x + y = 1 \n" );
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Algebra.Com's Answer #250136 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve each system by the substitution method \n" ); document.write( "a) \n" ); document.write( "2x - y = 4 \n" ); document.write( "2x - y = 3 \n" ); document.write( "------ \n" ); document.write( "1st equation: y = 2x-4 \n" ); document.write( "--- \n" ); document.write( "Substitute for y in 2nd and solve for \"x\": \n" ); document.write( "2x - (2x-4) = 3 \n" ); document.write( "2x-2x+4 = 3 \n" ); document.write( "4 = 3 \n" ); document.write( "--- \n" ); document.write( "Contradiction: Therefore No solution \n" ); document.write( "==========================================\r \n" ); document.write( "\n" ); document.write( "b) \n" ); document.write( "x + 3y = 2 \n" ); document.write( "-x + y = 1 \n" ); document.write( "--- \n" ); document.write( "1st equation: x = -3y+2 \n" ); document.write( "--- \n" ); document.write( "Substitute for \"x\" and solve for \"y\": \n" ); document.write( "-(-3y+2)+y = 1 \n" ); document.write( "3y-2 + y = 1 \n" ); document.write( "4y = 3 \n" ); document.write( "y = 3/4 \n" ); document.write( "--------- \n" ); document.write( "Since x = -3y+2, x = -3(3/4)+2 = -9/4+8/4 = -1/4 \n" ); document.write( "====================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |