document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=349890>Question 349890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a pot contains 6 liters at a concentration of 120 grams per liter. how much of the water should be boiled off to increase the concentration to 200 grams per liter?   i found x to equal 3.6 liters left over but i don't know what to do after that. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #250092 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=250092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a pot contains 6 liters at a concentration of 120 grams per liter. how much of the water should be boiled off to increase the concentration to 200 grams per liter?   i found x to equal 3.6 liters left over but i don't know what to do after that.<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "6 l * 120 gm/liter = 720 gm of stuff<BR>\n" );
document.write( "For 720 gm to be 200 gm/l, the water has to be 3.6 liters<BR>\n" );
document.write( "6 - 3.6 = 2.4 liters to boil off\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );