document.write( "Question 349919: Roger's age is 1 1/3 times Steven's age. Eight years ago, Roger's age was twice Steven's age. Find Roger's age. \n" ); document.write( "
Algebra.Com's Answer #250090 by mananth(16946)\"\" \"About 
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let steven's age be x
\n" ); document.write( "roger's age = 1 1/3 times stevens age.
\n" ); document.write( "=4/3 times = 4x/3
\n" ); document.write( "...
\n" ); document.write( "8 years ago
\n" ); document.write( "steven's age = x-8
\n" ); document.write( "roger's age = 4x/3 - 8
\n" ); document.write( "...
\n" ); document.write( "4x/3 -8 = 2(x-8)
\n" ); document.write( "(4x-24)/3 = 2x-16
\n" ); document.write( "x3
\n" ); document.write( "4x-24=3(2x-16)
\n" ); document.write( "4x-24=6x-48
\n" ); document.write( "6x-4x=48-24
\n" ); document.write( "2x=24
\n" ); document.write( "x=12 steven's age
\n" ); document.write( "Roger = 4/3 * 12
\n" ); document.write( "=16 years
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